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fgiga [73]
3 years ago
6

Which of the following is NOT a characteristic of a references page?

Mathematics
1 answer:
777dan777 [17]3 years ago
5 0
I need more information to help you.
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Can you help find the quotient for 4/5 ÷ 10
pochemuha

Answer:

2/25

Step-by-step explanation:

5 0
4 years ago
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In the equation 5 + 3x - 7 = 10, what are the like terms?
WITCHER [35]

Answer:

5 , -7 , 10

Step-by-step explanation:

8 0
3 years ago
Consider this equation: –2x – 4 + 5x = 8 Generate a plan to solve for the variable. Describe the steps that will be used.
horrorfan [7]
We are given the function <span>–2x – 4 + 5x = 8  and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

-2x + 5x =8+4
Then, do the necessary operations.

3x = 12
x = 4.
The variable x has a value of 4.</span>
6 0
4 years ago
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GIVING BRIANLIEST PLS HELP
Ivenika [448]

Step-by-step explanation:

a) Line AB ll DC

b) Line GH acts as a transversal.

c) <10 ; <12 , <9 ; <11

d) <8 = 180° - 120° = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<6 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<5 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<4 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<3 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<2 = <u>120</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

<1 = <u>60</u><u>°</u><u>(</u><u>Ans</u><u>)</u>

5 0
3 years ago
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A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th
mrs_skeptik [129]
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2).  Draw this to verify this statement.  Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height).  Subst. the values discussed above,   A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2).  Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section.   Doing the problem this way, we get (1/4) (3 sqrt(2) )^2.  Thus, 
A = (1/4) (9 * 2) = (9/2).  Same answer as before. 
4 0
4 years ago
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