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dem82 [27]
3 years ago
15

Which expression represents the 4th term in the binomial expansion of (e+2f)^10

Mathematics
1 answer:
butalik [34]3 years ago
7 0
The answer depends on what is meant by the "fourth term". By the binomial theorem, one answer could be

\dbinom{10}3e^3(2f)^{10-3}=120e^3(2f)^7=15360e^3f^7

By symmetry, another could be

\dbinom{10}3(2f)^3e^{10-3}=960e^7f^3
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Multiply negative 1 over 3 multiplied by 1 over 4. Which of the following is correct? negative 1 over 3 negative 1 over 4 negati
EleoNora [17]

Answer:

-1/12

Step-by-step explanation:

-1/3 * 1/4

Multiply the numerators

-1 *1 = -1

Multiply the denominators

3 *4 =12

numerator over denominator

-1/12

7 0
3 years ago
Find common ratio and series sum
Artyom0805 [142]

Answer:

Her total harvest over the

first 5 years that she owns the farm is 11277 kg

Step-by-step explanation:

Maggie is starting a small farm. In her first year, she harvests 90.000 kilograms of kale.

As she gets better at planting, fertilizing and pest control,

each year her harvest increases by 3%.

So,

In First year

She owns 90,000 kg

In Second year

She owns 90,000 kg and her harvest is increases by 3%.

i.e.,

90000 × 3 ÷ 100 = 2700

So, The increase in 90,000 kg kale is 2,700

Now,

90,000 + 2,700 = 92,700 kg

In Third year

She owns 92,700 kg and her harvest is increases by 3%.

i.e.,

92700 × 3 ÷ 100 = 2781

So, The increase in 92,700 kg kale is 2781

Now,

92,700 + 2,781 = 95,481 kg

In Fourth year

She owns 95,481 kg and her harvest is increases by 3%.

i.e.,

95481 × 3 ÷ 100 = 2846

So, The increase in 95,481 kg kale is 2846

Now,

95,481 + 2,846 = 98,345 kg

In Fifth year

She owns 98,354 kg and her harvest is increases by 3%.

i.e.,

98354 × 3 ÷ 100 = 2950

So, The increase in 98354 kg kale is 2950

Now,

98354 + 2950 = 101,295 kg

Now,

In First five years She owns

2700 + 2781 + 2846 + 2950 = 11277 kg

Thus, her total harvest over the first 5 years that she owns the farm is 11277 kg

<u>-TheUnknownScientist</u>

6 0
3 years ago
1/2 of a number is 32 what's the answer
AVprozaik [17]
64 !! because 32 x 2 is 64
3 0
3 years ago
I need help can you help me please
ozzi
Just multiple them together and u get 693
6 0
3 years ago
A certain code is a sequence of 7 digits. What is the probability of generating 7 digits and getting the code consisting of 1, 2
Oksana_A [137]

Answer:

The code has 7 digits:

Here you are asking:

"What is the probability that the code is consisting only of the digits {1, 2, 3, 4, 5, 6, 7}?"

Ok, first we must calculate the number of all the possible codes.

Suppose that each digit is an independent event.

Each one of those events has 10 possible outcomes {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

And we have 7 of those.

The total number of possible combinations is equal to the product of the number of outcomes for each event, then the total number of possible combinations is:

C = 10^7.

Now let's calculate the number of possible codes if we only use the digits in the restriction.

We can do exactly the same as above, but now in each case, we have 7 possible outcomes for each digit, then in this case the number of possible combinations is:

c = 7^7.

Now the probability of generating at random a code that only uses the digits  {1, 2, 3, 4, 5, 6, 7} is equal to the quotient between the number of codes that only use these digits, and the total number of possible codes.

P = c/C = (7^7)/(10^7) = (7/10)^7 = 0.082

4 0
3 years ago
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