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BartSMP [9]
3 years ago
14

Help please with question 5-8, show the solution

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
8 0

For each of these problems, remember SOH-CAH-TOA.

Sine = opposite/hypotenuse

Cosine = adjacent/hypotenuse

Tangent = opposite/adjacent

5) Here we are looking for the cosine of the 30 degree angle. Cosine uses the adjacent side to the angle over the hypotenuse. Therefore, cos(30) = 43/50.

6) We have an unknown side length, of which is adjacent to 22 degrees, and the length of the hypotenuse. Since we know the adjacent side and the hypotenuse, we should use Cosine. Therefore, our equation to find the missing side length is cos(22) = x / 15.

7) When finding an angle, we always use the inverse of the trigonometry function we originally used. Therefore, if sin(A) = 12/15, then the inverse of that would be sin^-1 (12/15) = A.

8) We are again using an inverse trigonometry function here. We know the hypotenuse, as well as the side adjacent to the angle. Therefore, we should use the inverse cosine function. Using the inverse cosine function gives us cos^-1 (9/13) = 46 degrees.

Hope this helps!

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Answer:

y=1/3x-5

Step-by-step explanation:

y=mx+b

Y=slope x+y-intercept

slope 2/6 = 1/3

y-int= -5

7 0
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{(1,4), (3,2).(-3,-2),(1,2).(-2,-3)} function or no funtions​
Nana76 [90]

Answer: not a function

Step-by-step explanation:

every x input must have only one y output.

(x,y)

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The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm. The process sta
svlad2 [7]

Answer:

H_0:\mu\geq56\\\\ H_a:\mu

Step-by-step explanation:

Null hypothesis (H_0): It is a statement about the population parameter that contains = , ≤  or ≥ signs.

Alternative hypothesis (H_a): It is also a statement about the population parameter but against the null hypothesis that contains = , <  or > signs.

Given : The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm.

here , Population parameter = \mu    [ Population mean ]

i.e. \mu

Objective :  Whether the mean is smaller than it is supposed to be.

Then, the set of hypothesis will be :

H_0:\mu\geq56\\\\ H_a:\mu

3 0
3 years ago
Find the value of x?
denis-greek [22]

If the arc is 60, the inscribed angle is 1/2 (60) = 30

If the arc is 70, the inscribed angle is 1/2 (70) = 35

the triangle is 30+35 +x=180

65+x =180

subtract 65 from each side

x=115


7 0
3 years ago
Acute △ABC with angles α, β, and γ is inscribed in a circle. Tangents to the circle at points A, B, and C intersect in points M,
SOVA2 [1]

Answer:

The measures of angles of triangle MNP are

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

Find the measure of arcs AB, BC and AC

we know that

The inscribed angle is half that of the arc it comprises.

so

\gamma=\frac{1}{2}[arc\ AB] ----> arc\ AB=2\gamma\\\alpha=\frac{1}{2}[arc\ BC] ----> arc\ BC=2\alpha\\\beta=\frac{1}{2}[arc\ AC] ----> arc\ AC=2\beta

step 2

Find the measure of angle M

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

M=\frac{1}{2}[arc\ AB+arc\ BC-arc\ AC]

substitute

M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]

step 3   

Find the measure of angle N

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]

substitute

N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]

step 4    

Find the measure of angle P

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]

substitute

P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]

5 0
3 years ago
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