The length of a rectangle is twice its width. if the area of the rectangle is 128 ft2 , find its perimeter.
1 answer:
Length(l)= 2w
Width(w)= w
Area(A) = l*w
A= 128 ft²
128= l*w
128= (2w)w
2w²= 128
w²= 64
w=√64= 8 ft
w= 8 ft
length(l)= 2w
l=2(8)
l=16 ft
P= 2l+2w
P=2(16)+2(8)= 32+16= 48ft
P= 48ft
Answer:
The Perimeter of this rectangle is 48 feet.
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