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Kisachek [45]
3 years ago
12

HELP ME PLEASE!

Mathematics
2 answers:
leva [86]3 years ago
7 0
The answer is choice A

The sample space is basically the set of all possible outcomes. Each outcome is a pair of results from drawing a card coupled with spinning a spinner. 

Table A represents all of the possible outcomes properly. The card results are along the column on the left side. The spinner results along the row up at the top. Each cell is an intersection of the left and top result. For example, row1,column3 has "red,purple" to indicate you got "red" on the spinner and "purple" on the card. Each cell in table A is correctly labeled.

The other tables (B, C, D) are improperly labeled in at least one cell. 
* Table B has "blue, green" in the top row" middle cell when it should be "blue, purple"

* Table C has "green, green" in the upper left corner when it should be "green, purple"

* Table D has "blue, blue" in the bottom middle cell when it should be "blue, green". Saying "blue,blue" is impossible as there isn't a blue card.

The three items mentioned above help us eliminate choices B through D.
fomenos3 years ago
6 0

Answer:what is the answer?

Step-by-step explanation:

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Julie found a shoe sale. She bought 8 pairs of shoes for a total of $45.50. She decided to buy 5 pairs of shoes for her sister a
Andrew [12]

Step-by-step explanation:

72 i rounded it to that

3 0
4 years ago
The relationship between the distance run and the time for Amy can be represented by the equation Y equals 17.45X, where she ran
Kipish [7]

Question;

Assumption:

Let us assume Brandon's running speed is = 18.30 and

Ruben's running speed is = 16.50 and

Answer:

The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;

Brandon → Y₁ = 18.3·X₁ and

Ruben → Y₂ = 16.5·X₂

Step-by-step explanation:

The equation is of the form

Y = 17.45·X

That is Amy ran Y meters in X seconds

Therefore we have

17.45 = \frac{Y}{X} or the value 17.45 is the running speed of Amy

Therefore, where the running speed of Brandon is 18.30  and the running speed of Ruben is 16.50  we have

Y meters ran by Brandon in X seconds given by

Y₁ = 18.3·X₁ and

For Ruben we have Y meters ran in X seconds given by

Y₂ = 16.5·X₂.

5 0
4 years ago
Read 2 more answers
Solve (3x+8)(y^2+4) dx +4
Anna35 [415]

It's been four years since I last did a problem of this particular nature. :)


Try this: divide both sides of the given equation by (x^2-5x+6), obtaining


(3x+8)(y^2+4)          + 4y(x^2+5x+6) dy

-------------------- dx + ------------------------- dy = 0

x^2+5x + 6                         x^2+5x + 6


This gives us:


(3x+8)(y^2+4)

-------------------- dx + 4ydy = 0

(x+2)(x+3)


Now divide all 3 terms by y^2+4:


3x+8

--------------- dx + 4ydy = 0 This completes the separation of variables.

(x+2)(x+3)


Now we'll need to integrate each of the 3 terms.


3x+8

--------------- dx + 4ydy = 0 can be re-written in the form

(x+2)(x+3)


3x     +8              A           B

--------------- = --------- + ---------- We will need to determine the values

(x+2)(x+3)        x+2       x+3 of A and B (partial fraction expansion).


I trust you know how to do this; if not, let me know and I'll help you with that also.


I obtained B=2 and A = 1. You might want to verify that 1/(x+2) + 2/(x+3) =


3x+8

-------------- .

(x+2)(x+3)


Integrating the left side of this d. e. results in ln(x+2) + ln(x+3).

Integrating 4ydy results in 4*y^2/2, or 2y^2.


Integrating 0 results in a constant, C.


Thus,


ln(x+2) + ln(x+3) + 2y^2 = C is the solution of this d. e.


7 0
3 years ago
How to solve number 44
solniwko [45]
OK. 

Let's say a member and a non member each visit the garden ' V ' times.

The non-member's cost for each visit is  $6 .
The non member's cost for ' V ' visits is  6 V .
His total cost for the year is  6 V .

The member's cost for each visit is $3.
The member's cost for ' V ' visits is  3V .
His total cost for the year is  3V  +  the  $24 to join.

We want to know what ' V ' is  (how many times each one can visit)
if their total costs are the same.

So let's just write an equation that SAYS their costs are the same,
and see what ' V ' turns out to be.

             Non-member's cost for the year =  Member's cost for the year

                                                            6 V  =  3 V + 24

Subtract  3V  from each side:          3 V  =            24

Divide each side by  3 :                       V  =              8  .

-- If they both visit the garden 1, 2, 3, 4, 5, 6, or 7 times in the year,
the member will spend MORE than the non member.

-- If they both visit the garden 8 times in the year,
they'll both spend the same amount.  ($48)

-- If they both visit the garden MORE than 8 times in the year,
the member will spend LESS than the non-member.
______________________________________________ 

That was the algebra way to do it.

Now here is the cheap, sleazy, logical, easy way to do it:

The non-member spends (6 - 3) = $3 MORE than the member for each visit ?

After how many visits does the $3 more each time add up to the $24 that
it cost the member to join for the year ?

           $24 / $3  =  8 visits  .
5 0
4 years ago
What is 5906+689*56/2-3
hoa [83]

Answer:

25195

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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