Question

A fast-food restaurant offers 6 different burgers, 5 different side orders, 7 different flavor drinks, and 8 different flavors of ice cream. In how many ways can a combo containing 2 burgers, 2 different sides, 2 different flavor drinks, and 2 ice cream flavors be made?

Answer 1

Answer:

Total no of pay is 113400

Explanation:

Given data:

No. of burger 6

order of different sides 5

No. of flavor drinks 7

No. of different ice cream 8

for 2 burgers from 6 different burger $= ^6C_2$

for 2 different side from 6 different sides $= ^5C_2$

for 2 different flavor drinks from 7 different burger $= ^7C_2$

for 2 ice cream from 8 different burger$= ^8C_2$

total no of way is $= ^6C_2 \times ^5C_2 \times ^7C_2 \times ^9C_2$

$= 15 \times 10\times 21 \times 36$

                             = 113400