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3 years ago

I don’t understand this, can somebody help

Mathematics

1 answer:

Alexandra [31]3 years ago

8 0

He didn't make it reflect across the x axis as well

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A box of light fixtures cost $43 if you had $600 and I bought is moving boxes as you could how much money would you have left

Mademuasel [1]

Answer:

13 Boxes with $41 left over

Step-by-step explanation:

$600/$43 = 13.9 (so she can buy 13 boxes of light fixtures)

$43 x 13 = $559

$600-$559=$41 left over

6 0

3 years ago

Help!!!!!!!!!!!!!!!!!!!!!!! SAY WHICH ONE YOU ARE ANSWERING!!!!!!!!!!!!!!!!!!!!

Over [174]

Answer:

100

Step-by-step explanation:

estimate 99.056603

Hope this helps!

Please mark brainliest!

Have a nice day!

7 0

3 years ago

The product of two consecutive positive odd numbers is 195.By constructing a quadratic equation and solving it, find the two num

Tomtit [17]

Step-by-step explanation:

x = one odd number

the second odd number is (x+2), as both are consecutive.

so,

x × (x + 2) = 195

x² + 2x = 195

x² + 2x - 195 = 0

the formula to solve this is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 2

c = -195

x = (-2 ± sqrt(4 - 4×1×-195))/(2×1) =

= (-2 ± sqrt(4 + 4×195))/2 = (-2 ± sqrt(784))/2 =

= (-2 ± 28)/2 = -1 ± 14

x1 = -1 + 14 = 13

x2 = -1 - 14 = -15 which is invalid as the numbers are positive.

so, the two numbers are 13 and 15.

5 0

3 years ago

HELPPPP!!!! Need the answer ASAP!!

Greeley [361]

Given that the functions $f(x)=x+4$ and $g(x)=x^{3}$

We need to determine the value of the function $(g \ {\circ} f)(-3)$

First, we shall determine the composition of the function $(g \circ f)(x)$

Function $(g \circ f)(x)$ :

Let us determine the function $(g \circ f)(x)$

Thus, we have;

$(g \circ f)(x)=g[f(x)]$

$=g[x+4]$

$=(x+4)^3$

$(g \circ f)(x)=x^3+3x^2(4)+3x(4)^2+(4)^3$

$(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, the function is $(g \circ f)(x)=x^3+12x^2+48x+64$

Value of the function $(g \ {\circ} f)(-3)$ :

The value of the function can be determined by substituting x = -3 in the function $(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, we have;

$(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64$

Simplifying the terms, we get;

$(g \circ f)(-3)=-27+12(9)+48(-3)+64$

$(g \circ f)(-3)=-27+108-144+64$

$(g \circ f)(-3)=1$

Thus, the value of the function $(g \ {\circ} f)(-3)$ is 1.

8 0

3 years ago

No solution for 3x+9+4z+x

zhuklara [117]

what is the original equation and then maybe i can help you solve

5 0

4 years ago