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FromTheMoon [43]
2 years ago
8

Question 1 of 10

Mathematics
1 answer:
Darya [45]2 years ago
7 0

Answer:

Log₆ (A⁵C² / D⁶) = –13

Step-by-step explanation:

From the question given above,

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

Log₆ (A⁵C² / D⁶) =?

Recall:

Log MN / U = Log M + Log N – Log U

Therefore,

Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶

Recall:

Log Mⁿ = nLog M

Thus,

Log₆ A⁵ + Log₆ C² – Log₆ D⁶

= 5Log₆ A + 2Log₆ C – 6Log₆ D

Log₆ A = 1

Log₆ C = 3

Log₆ D = 4

= 5(1) + 2(3) – 6(4)

= 5 + 6 – 24

= 11 – 24

= –13

Therefore,

Log₆ (A⁵C² / D⁶) = –13

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Step-by-step explanation:

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3 years ago
If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f
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Step-by-step explanation:

The harmonic motion is described by the following equation.

x(t) = 3\cos{\pi t}

What is the first occurrence of a value of t for which x = 0?

This is t when x(t) = 0. So

x(t) = 3\cos{\pi t}

3\cos{\pi t} = 0

\cos{\pi t} = \frac{0}{3}

\cos{\pi t} = 0

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

\arccos{\cos{\pi t}} = \arccos{0}

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