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Sauron [17]
3 years ago
15

There are 62rows of 9 chairs in the movie theater about how many chairs are there

Mathematics
2 answers:
dem82 [27]3 years ago
4 0
It's easy it's just 62×9 it equals 558
Temka [501]3 years ago
4 0
First, do 62 times 9 and that equals 558 or five hundred fifty-eight
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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn
Gekata [30.6K]

Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i) for all i,i',j and for X_n in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that j=2, i=1, i'=0 then we have this:

P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}

Because we can only have j=2, i=1, i'=0 if we have this:

Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0, from definition given X_n = Y_n + Y_{n-1}

With i=1, i'=0 we have that Y_n =1 , Y_{n-1}=0, Y_{n-2}=0

So based on these conditions Y_{n+1} would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that j=2, i=1, i'=2 for this case in order to satisfy the definition then Y_n =0, Y_{n-1}=1, Y_{n-2}=1

But on this case that means X_{n+1}\neq 2 and on this case the probability P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0, so we have a counter example and we have that:

P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i) for all i,i', j so then we can conclude that we don't have a Markov chain for this case.

6 0
3 years ago
Rewrite in simplest radical form <br> 1<br> x<br> −3<br> 6
vesna_86 [32]
1 / (x-3/6)
1 / x-1/2
x1/2
3 0
3 years ago
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Last weekend you attended a concert. You spent a total of $156. Twenty percent of the cost was for a parking pass. The rest of t
kirill [66]

Answer:

32.1 dollars each ticket is the answer

7 0
3 years ago
Read 2 more answers
4.3 Mr Mokwebo 's two sons, Refentse and Tokelo have just passed grade 7 and grade 9 respectively. He will give them some money
Bumek [7]

The amount of money each of Mr Mokwebo 's two sons; Tokelo and Refentse will get is R116 and R95 respectively.

<h3>How to write and solve equation:</h3>

  • Amount needed to buy chocolate = R253
  • Tokelo's money = x
  • Refentse's money = x - 21

Total amount needed = Tokelo's money + Refentse's money

253 = x + (x - 21)

253 = x + x - 21

253 = 2x - 21

253 - 21 = 2x

232 = 2x

divide both sides by 2

x = 232/2

x = 116

Therefore,

Tokelo's money = x = R116

Refentse's money = x - 21

= 116 - 21

= R95

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6 0
1 year ago
(35 Points)<br> Evaluate ƒ(x) when x = 6.
pychu [463]

The value of the function is 6

Step-by-step explanation:

The function that we have in this problem is

f(x)=\left \{ {{3x^2+1}, -4

This means that:

when x is between -4 (excluded) and 6 (excluded), the value of the function is 3x^1+2

when x is between 6 (included) and 9 (excluded), the value of the function is 6

In this problem, we are asked to evaluate f(x) when x = 6. Therefore, we are in the second case: therefore, the value of the function is 6,

f(x)=6

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8 0
3 years ago
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