Question

(35 Points) Evaluate ƒ(x) when x = 6.

Answer 1

The value of the function is 6

Step-by-step explanation:

The function that we have in this problem is

$f(x)=\left \{ {{3x^2+1}, -4$

This means that:

when x is between -4 (excluded) and 6 (excluded), the value of the function is $3x^1+2$

when x is between 6 (included) and 9 (excluded), the value of the function is 6

In this problem, we are asked to evaluate f(x) when x = 6. Therefore, we are in the second case: therefore, the value of the function is 6,

$f(x)=6$

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