Solve the following system of equations: 4x+5y=23 -3x-7y=-14
1 answer:
Basically you're solving for both variables here.
I prefer elimination method so that is what I used.
I started off by multiplying each equation in order to get one of the variables at the same value so it would be possible to cancel it out.
Multiplying the first equation by 3 gave me,
12x + 15y = 69
Then I multiplied the second equation by 4,
-12x + 28y = -56
As you can see, it's not possible to cancel out the x variable.
12x + 15y = 69
+(-12x + 28y = -56)
_____________
13y = 13
Then just solve for y which gives you -1.
After you have one variable solved simply insert it into one of the original equations to find the other variable.
4x + 5(-1) = 23
4x - 5 = 23
4x = 28
x = 7.
And there you have it! Hope this helped!
I prefer elimination method so that is what I used.
I started off by multiplying each equation in order to get one of the variables at the same value so it would be possible to cancel it out.
Multiplying the first equation by 3 gave me,
12x + 15y = 69
Then I multiplied the second equation by 4,
-12x + 28y = -56
As you can see, it's not possible to cancel out the x variable.
12x + 15y = 69
+(-12x + 28y = -56)
_____________
13y = 13
Then just solve for y which gives you -1.
After you have one variable solved simply insert it into one of the original equations to find the other variable.
4x + 5(-1) = 23
4x - 5 = 23
4x = 28
x = 7.
And there you have it! Hope this helped!
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<h2>Answer:</h2>
Option: C is the correct answer.
C.
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Option: C
Answer:
3,333,333 spacecraft
Step-by-step explanation:
To get the number of spacecraft that would fit between earth and moon <em>divide the distance by the length of the spacecraft</em>.
When is divided by 360 the quotient will be 3,333,333 and the remainder will be 120.
It means 3,333,333 Apollo 11 spacecraft will fit between earth and moon but still 120 feet will remain and no more spacecraft can completely fit in it.