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3 years ago

What is the area of a trapezoid that has bases measuring 19 centimeters and 23 centimeters, and a height of 14 centimeters?

1 answer:

6 0

Area of a trapezoid, A = 1/2 × (a + b) h, where a = 19 cm, b = 23 cm & h = 14 cm.

By substitution, we have

A = 1/2 × (19 + 23)14

= 1/2 × 14(19 + 23)

= 1/2 × 14(42)

= 7(42)

= 294 sq. cm

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Answer:

$g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}$

Step-by-step explanation:

Given function,

$g(x) = -\frac{2}{3}x-5$

Step 1 : Replace g(x) by y:

$y = -\frac{2}{3}x-5$

Step 2 : Swap x and y:

$x = -\frac{2}{3}y-5$

Step 3 : Solve the equation for y ( isolate y in the left side ):

$x +\frac{2}{3}y=-5$

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$y=\frac{3}{2}(-5-x)$

$y=-\frac{15}{2}-\frac{3}{2}x$

$y=-\frac{3}{2}x-\frac{15}{2}$

Step 4: Replace y by $g^{-1}(x)$ :

$g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}$

Hence, the inverse of the function g(x) is $g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}$ .

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3 years ago

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