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wolverine [178]
3 years ago
12

NEED HELP ASAP!!!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0
14. To get the length of each side, you will have to find the square root of 189 to find what two numbers multiplied by itself will get to that number. The square root of 189 is about 13.7, to the nearest tenths is 14
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Question 20
zimovet [89]

9514 1404 393

Answer:

  (d)  A = 18 units²

Step-by-step explanation:

Line CE can be considered to be the base of two triangles. It is 6 units long. The upper triangle is 4 units high, and the lower triangle is 2 units high. The formula for the area of a triangle is ...

  A = 1/2bh

Then the sum of the areas of the two triangles is ...

  A = 1/2(6)(4) +1/2(6)(2) = 12 +6 = 18

The area of the polygon is 18 square units.

7 0
2 years ago
Money in a savings account is compounded continuously over time, t, and is modeled by the function
bezimeni [28]

Answer:

  1.7% compounded continuously

Step-by-step explanation:

The model used for continuous compounding is ...

  f(t) = Pe^(rt)

where P is the principal amount, and r is the interest rate being compounded. Assuming a typo in your given equation, you have ...

  f(t) = 1000·e^(0.017t)

Matching the various parts of the equation, we see that P = 1000 and r = 0.017 = 1.7%.

The balance grows at a continuous rate of 1.7%.

5 0
3 years ago
Good guys will pay you $3,800 a year for 10 years in exchange for $31,300 today. what interest rate will you earn on this annuit
Anuta_ua [19.1K]
I hope this helps you




in a year $3800



in 10 year 10.3800=38000



38000-31300=6700


in 10 year rate 6700


for a year rate ?




?.10=6700


?=670
5 0
3 years ago
3
Furkat [3]

How many did he lose? Can you tell us how much he lost?

6 0
3 years ago
If the 9th term of an ap is 1/7 and the 7th term os 1/9 find the 63rd term
Mnenie [13.5K]

Answer:

a_{63} = 1

Step-by-step explanation:

The n th term of an arithmetic progression is

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

use the 9 th term and 7 th term to find a and d

a_{9} = a + 8d = \frac{1}{7} → (1)

a_{7} = a + 6d = \frac{1}{9} → (2)

Subtract (2) from (1) term by term

2d = \frac{2}{63} ⇒ d = \frac{1}{63}

Substitute this value into (2) and solve for a

a + \frac{6}{63} = \frac{1}{9}

a = \frac{1}{9} - \frac{6}{63} = \frac{1}{63}

Hence

a_{63} = \frac{1}{63} + \frac{62}{63} = 1


5 0
3 years ago
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