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alexira [117]
4 years ago
11

Me.White decided to install a pool. The pool had a width of 6 yards and an area of 54 square yards. What is the length of Mr. Wh

ites pool ?
Mathematics
2 answers:
m_a_m_a [10]4 years ago
4 0
The equation for area is l (length) * w (width). So, to find the length, we just have to divide the area by the width.

The equation to find the length will look something like this: area/width = length. Or in this case: 54/6 = 9, where 54 is the area, 6 is the width, and 9 is the length.

So the length of Mr. White’s pool is 9 yards long.
Mazyrski [523]4 years ago
3 0

Answer:

the answer is 9 yards

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skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

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Now factor out what's common within each set of parenthesis:

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(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

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x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

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3 years ago
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Ugo [173]

Answer:

the  mean and standard error of the mean are 200 and 2 respectively.

Step-by-step explanation:

Given that ;

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standard deviation of the infinite population σ = 18

A population  is the whole set of values, or individuals you are interested in, from an experimental study.

The value of population characteristics such as the  Population mean (μ), standard deviation (σ) are said to be known as the population distribution.

From the given information above;

The sample size is large and hence based on the central limit theorem the mean of all the means is same as the population mean 200.

i.e

\mu = \bar \mu_x = 200

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\mathbf{standard \ error \ of \ mean = \dfrac{\sigma}{\sqrt {n}}}

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Hence either AR and BS are in same line  or parallel.

But they are radii of different circles.

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