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3 years ago

8 meters increased by 25%

1 answer:

const2013 [10]3 years ago

4 0

Answer:
10 meters

Explanation:
First, we will compute 25% of 8 as follows:
25% of 8 = 25% * 8
= 0.25 * 8
= 2

Now, 8 increased by 25% of 8 means that we will add the 25% of the 8 that we computed to the 8 we have.
Therefore:
8 increased by 25% = 8 + 25% of 8
= 8 + 2
= 10 meters

Hope this helps :)

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Flow many years after the tree is planted does the model predict the tree will reach a height of 65 feet?

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A mass weighing 16 pounds stretches a spring (8/3) feet. The mass is initially released from rest from a point 2 feet below the

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Answer with Step-by-step explanation:

Let a mass weighing 16 pounds stretches a spring $\frac{8}{3}$ feet.

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Mass= $m=\frac{16}{32}$

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Mass,m= $\frac{1}{2}$ Slug

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$16=\frac{8}{3} k$

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A damping force is numerically equal to 1/2 the instantaneous velocity

$\beta=\frac{1}{2}$

Equation of motion :

$m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}+f(t)$

Using this equation

$\frac{1}{2}\frac{d^2x}{dt^2}=-6x-\frac{1}{2}\frac{dx}{dt}+10cos(3t)$

$\frac{1}{2}\frac{d^2x}{dt^2}+\frac{1}{2}\frac{dx}{dt}+6x=10cos(3t)$

$\frac{d^2x}{dt^2}+\frac{dx}{dt}+12x=20cos(3t)$

Auxillary equation

$m^2+m+12=0$

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Complementary function

$e^{\frac{-t}{2}}(c_1cos\frac{\sqrt{47}}{2}+c_2sin\frac{\sqrt{47}}{2})$

To find the particular solution using undetermined coefficient method

$x_p(t)=Acos(3t)+Bsin(3t)$

$x'_p(t)=-3Asin(3t)+3Bcos(3t)$

$x''_p(t)=-9Acos(3t)-9sin(3t)$

This solution satisfied the equation therefore, substitute the values in the differential equation

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$(3B+3A)cos(3t)+(3B-3A)sin(3t)=20cso(3t)$

Comparing on both sides

$3B+3A=20$

$3B-3A=0$

Adding both equation then, we get

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$3A=20-10=10$

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Particular solution, $x_p(t)=\frac{10}{3}cos(3t)+\frac{10}{3}sin(3t)$

Now, the general solution

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3 years ago

Read 2 more answers

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Masja [62]

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