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3 years ago

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1 answer:

7 0

$\sf Hello!$

$\sf Let\: the \:required$ % $\sf be\: x$

$\sf Then,$

$\sf x$ % × $\sf 50 = \sf 9$

⇒ $\dfrac{\sf x}{\sf 100} × \sf 50 = \sf 9$

⇒ $\dfrac{\sf x}{\sf 2} = \sf 9$

⇒ $\sf X = \sf 9 × 2$

⇒ $\boxed{\sf x = 18}$

$\sf Therefore,$
$\sf D.\: 18$ % $\sf of \:50\: is \:9$

~ $\sf iCarl$

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