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Zinaida [17]
4 years ago
12

.

Mathematics
1 answer:
brilliants [131]4 years ago
7 0
\sf Hello!

\sf Let\: the \:required % \sf be\: x

\sf Then,

\sf x % × \sf 50 = \sf 9

⇒ \dfrac{\sf x}{\sf 100} × \sf 50 = \sf 9

⇒ \dfrac{\sf x}{\sf 2} = \sf 9

⇒ \sf X = \sf 9 × 2

⇒ \boxed{\sf x = 18}

\sf Therefore,
\sf D.\: 18 % \sf of \:50\: is \:9

~ \sf iCarl
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