A) force justified.
If you open up Word (or probably any word processor) and hover over the alignment options in the ribbon (or format the paragraph), it tells you what each one is, and the option that ensures the characters are spread evenly between the margins is labeled "justified."
Answer:
This is not true
Explanation:
The optimal Huffman code is used to encrypt and compress text files. It uses fixed-length code or variable-length code for encryption and compression of data.
The professor's character code is similar to Huffman's variable-length coding which uses variable length od binary digits to represent the word strings. The file size of the text file above is;
= 6 x 1 + 2 x 2 + 3 x 2 + 2 x 2 + 8 x 1 = 28 bits
This would be the same for both cases.
The encrypt would be the problem as the encoded and decoding of the characters B and E may cause an error.
Answer:
suppose i was i would tell them i dont know and walk away
Explanation:
in thoery this is correct
you said suppose so i answerd
there is no use in reporting or getting this taken down
nether is it right
im not stealing points
Because in thoery its an answer
<em><u>THIS IS MY PROTEST</u></em>
Answer:
Output explanation to the given code can be defined as follows:
Explanation:
In A the output is 0
, It will return fork value of the child process that is 0. so, 0 is printed during child process.
In B the output is 2650
, in which the getpid() method returns the child process id value that is 2650.
In C the output is 140, As it is declared in key, all process have their own "value" copies. 20 are inserted during childhood, so 140 are written.
In D the output is 2650, its fork() method returns the child ID to the parent process. so the value 2650 is printed.
In E the output is 2600, Its getpid() method will returns parent process id that is equal to 2600.
In F the output is 120 Since the value is declared in primary, all process so their own "value" copies. 120 will be printed during process.
The issue arises because the string you are trying to print is not a string, rather a float value. Item1, item2 and item3 are strong values (if you type some alphabets in it and not just numbers), but itemonecost, itemtwocost, and itemthreecost are explicitly type casted to float. In line 22, 23, and 24 you’re trying to print a float, by adding it with the string. One cannot add numbers to string. Rather you can type cast the itemcost to string while printing.
Add str(itemonecost) instead of itemonecost in print statement. Do this for other float variables too.
However do note that there are multiple ways to correct this issue, and I’ve just pointed one out.
