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laila [671]
3 years ago
6

You need to perform maintenance on a router and need to temporarily reroute traffic through another office. which would be the b

est way to perform this action?
Computers and Technology
1 answer:
Whitepunk [10]3 years ago
3 0
<span>In order to perform maintenance on a router and need to temporarily reroute traffic through another office  the best way to perform this action would be to configure a static route on the router.
</span>By doing this, the router will use the manually-<span>configured routing entry to send the packets.</span>
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13. You're doing research for a paper. When would you use an indirect citation?
Whitepunk [10]

Answer:

D

Explanation:

d is the answer

5 0
2 years ago
Give a tight bound on the number of times the z = z + 1 statement is executed. i = 2 while ( i &gt; 1 ) { i = floor(i/2) z = z +
Alinara [238K]

Answer:

zero ( 0) times.

Explanation:

In the code;

i = 2

while ( i > 2){

     i = floor( i/2 );

     z = z + 1;

}

the variable " i " is assigned the integer " 2 ", then the while statement loops with a condition of a greater " i " value and divides the value by two for every loop.

But in this case, the while statement is not executed as the value of " i " which is 2 is not greater than but equal to two.

4 0
2 years ago
Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

6 0
3 years ago
(BRAINLIEST FOR FIRST CORRECT ANSWER) Mark (all) the statements that best describe the use of spreadsheets and tables in present
mel-nik [20]

the answer is Headers should be descriptive of the cell content, The font size should be at least 18-point. hope this helps!!!

5 0
3 years ago
When developing an estimate, which of the following items is typically marked up with the highest percentage rate?
dmitriy555 [2]

Answer: D. Labor

Explanation:

8 0
2 years ago
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