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il63 [147K]
3 years ago
9

A student solved this problem and said the answer was 5 miles.

Mathematics
2 answers:
Fofino [41]3 years ago
8 0
Greetings!

Option C would be correct.

3 + 4 + 5 = 13 therefore, C is the best answer.

Hope this helps!

~Lex
melomori [17]3 years ago
8 0
I think the answer is C. No, the answer is not reasonable. It should be about 13 miles because of the fact that 3 miles+ 4 miles +5 miles =12 miles, which is close to 13. Hope this helps!
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nignag [31]

Answer:

6x + 4 - 1/100 = 77.5

Step-by-step explanation:

Inc shipping all shirts 77.49

Shirt individual cost = 12.25

We find the division first = 77.49-3.99 = 73.5  = 73 1/2

Then we divide 73.5 / 12.25 = 6

Then we have our equation

6x + 4 - 1/100 = 77.5

7 0
3 years ago
Consider the function f(x). Select all of the following that include a vertical stretch of f(x)
zhenek [66]

Answer:

F , D, A

Step-by-step explanation:

As we know vertical stretch of f(x)  happens when we chane the value of the patameter a in this general form:

y = a. f(k(x-d))+ c  

when  |a| > 1 because When |a| > 1 (when a is greater than 1), the function is stretched vertically by a dilation factor of |a|.

So we choose, F , D, A

4 0
3 years ago
Read 2 more answers
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
Can someone please give me the answers to this? ... please ...
Hoochie [10]

Step-by-step explanation:

come on ! based on all the other questions that have been answered AND explained you should be able to find these answers yourself now. what is still unclear ?

distance between 2 points (x1, y1) and (x2, y2):

Pythagoras : c² = a² + b²

c is the connection between the 2 points (and which length we need to find).

c = sqrt(a² + b²)

a and b are differences of the x coordinates and the differences of the y coordinates of these 2 points.

a = x1 - x2

b = y1 - y2

this is simply because, when you look at the coordinate grid, these 3 items make a right-angled triangle.

don't worry about any negative values for a and b, as the square eliminates the negative sign.

midpoint between 2 points :

we could use Pythagoras again for this, but the end result is so simple, we can skip this.

at the end the coordinates of the midpoint of 2 points (x1, y1) and (x2, y2) are

((x1+x2)/2, (y1+y2)/2)

find the other endpoint (x2, y2), when you have one endpoint (x1, y1) and the midpoint (xm, ym) :

from above you know

xm = (x1+x2)/2

2×xm = x1 + x2

x2 = 2×xm - x1

and in the same way

ym = (y1+y2)/2

2×ym = y1 + y2

y2 = 2×ym - y1

and you can read a graph, right ?

if not it is high time to learn that very simple and basic skill :

the x coordinate of a point is how many units right (positive) or left (negative) from the center point it is.

the y coordinate of a point is how many units above (positive) or below (negative) from the center point it is.

the center point is always (0, 0).

so, what else do you need ?

I am very busy explaining things. I should not spend my little time doing the basic calculations for you (that I could train a monkey to do).

so, please, oil your brain machinery by following the instructions and formulas using the actual numbers and see how the results build out of this.

if you run into further problems, please ask me for additional explanations.

8 0
2 years ago
The image of the point (-6, -2) under a translation is (-4,2). Find the coordinates of the image of the point (-3, 4) under the
QveST [7]

ANSWER

(-1, 8)

EXPLANATION

First we have to find the rule for this translation.

The image of the x-coordinate of the given point is 2 untis more than the point, so the rule for the horizontal translation is to add 2.

The image of the y-coordinate of the given point is 4 units more than the point, so the rule for the vertical translation is to add 4:

(x,y)\rightarrow(x+2,y+4)

Therefore, the image of point (-3, 4) under the same translation is:

(-3,4)\rightarrow(-3+2,4+4)=(-1,8)

4 0
9 months ago
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