The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
0.00998 Inches
Step-by-step explanation:
Thickness of the light bulb filament = 0.01 Inch
Allowable error = 2%.
2% of 0.01 = 0.02 X 0.01 =0.0002 Inch
Therefore, the allowable thickness of the bulb filament

We can then calculate the least allowable thickness of the filament as:

The least allowable thickness of the filament is 0.00998 Inches.
Answer:
0.08268 is what I got
Step-by-step explanation:
I hope it correct
It would be : 0.35 , 0.4 , 0.7 .
Hope This Helps You!
Good Luck Studying :)
Answer:
A
Step-by-step explanation:
The form (2x-3)(5x+9) is fully factored. To determine if it is equivalent, multiply the parenthesis out.
(2x-3)(5x+9) = 10x² - 15x + 18x - 27 = 10x² + 3x - 27
Yes this is equivalent.
The solution is A.