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prohojiy [21]
3 years ago
8

The system of equations 3x + 9y^3= -21, 13y^3+4x=-1 has exactly one solution.

Mathematics
1 answer:
drek231 [11]3 years ago
8 0

Answer:

\huge\boxed{(-88,3)}

Step-by-step explanation:

\sf 3x + 9y^3 = -21  -------------------------- (1)

\sf 13y^3+4x= -1  -------------------------- (2)

Multiply Eq. (1) by 13 and (2) by 9

<u>Equation (1):</u>

\sf 13(3x+9y^3) = -21 * 13

\sf 39x + 117y^3=-273 --------------------(3)

<u>Equation (2):</u>

\sf 9(13y^3+4x) = -1* 9

\sf 117y^3 + 36x = -9 ------------------------(4)

Subtract Eq. (2) from (1)

\sf 39x+117y^3-117y^3 -36x=-273+9  

39x - 36x = -264

3x = -264

Dividing both sides by 3

x = -88

\rule[225]{225}{2}

<u>Put x = -88 in Eq. (1)</u>

3(-88)+9y³ = -21

-264 + 9y³ = -21

9y³ = -21 + 264

9y³ = 243

Dividing both sides by 9

y³ = 27

Taking cube root on both sides

y = 3

\rule[225]{225}{2}

Ordered Pair = (x,y) = (-88,3)

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>

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The tough part is the number of drinks.
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