I don’t know the answer sorry
Answer:
8.20in³
Step-by-step explanation:
Given V = πr²h
r is the radius = 1.5in
h is the height = 6in
thickness of wall of the cylinder dr = 0.04in
top and bottom thickness dh 0.07in+0.07in = 0.14in
To compute the volume, we will find the value of dV
dV = dV/dr • dr + dV/dh • dh
dV/dr = 2πrh
dV/dh = πr²
dV = 2πrh dr + πr² dh
Substituting the values into the formula
dV = 2π(1.5)(6)•(0.04) + π(1.5)²(6) • 0.14
dV = 2π (0.36)+π(1.89)
dV = 0.72π+1.89π
dV = 2.61π
dV = 2.61(3.14)
dV = 8.1954in³
Hence volume, in cubic inches, of metal in the walls and top and bottom of the can is 8.20in³ (to two dp)
Answer:
75
Step-by-step explanation:
45*1/3=15
15*5=75
Answer:
{x,y} = {3,-2}
Step-by-step explanation:
// Solve equation [1] for the variable y
[1] y = 2x - 8
// Plug this in for variable y in equation [2]
[2] 3x - 2•(2x-8) = 13
[2] -x = -3
// Solve equation [2] for the variable x
[2] x = 3
// By now we know this much :
x = 3
y = 2x-8
// Use the x value to solve for y
y = 2(3)-8 = -2
Solution :
{x,y} = {3,-2}
