The histogram is especially useful in comparing mean and median values of a variable. We have that 5.5+6+7+10+7.5+8+9.5+9+8.5+8+7+7.5+6+6.5+5.5=111.5 Since there are 15 values, their mean is 111.5/15=7.43 which is very close to the mean. We also have that 7 onservations are lower than 7.4 while 8 are bigger than 7.4; hence, the diagram is rather balanced and not left-skewed. We cannot tell immediately which one is larger since the values are too close. Any such random process can usually be approximated to a greater or smaller degree by a normal curve; the more points, the better. The histogram shows this (it is kind of a discrete normal curve); all points except 4 will be in this interval of bars.
First set up a proportion
240/160 = 320/200
Cross multiply and if the left equals the right it is similar.
Answer:
maybe B
Step-by-step explanation:
cuz interquaInterquartile is just a range of q1-q3
Answer:
47/12, or 3 11/12
Step-by-step explanation:
9 1/2 - 5 7/12 > convert to improper fractions
19/2 - 67/12
make same denominator (12)
19/2 * 6 = 114/12
114/12 - 67/12 = 47/12
19.5
Step-by-step explanation:
u just divide 39 by 2 and get 19.5
