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2 years ago

What is “One third of the opposite of a number is less than 12?”

Mathematics

1 answer:

nirvana33 [79]2 years ago

4 0

Answer:

$\frac{1}{3}(-x)$ <12

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Solve the inequality. 2(4+2x)≥5x+5 A. x≤−2 B. x≥−2 C. x≤3 D. x≥3

LenaWriter [7]

$\text{Solve for x:}\\\\2(4+2x)\geq5x+5\\\\\text{Use the distributive property}\\\\8+4x\geq5x+5\\\\\text{Subtract 5x from both sides}\\\\8-x\geq5\\\\\text{Subtract 8 from both sides}\\\\-x\geq-3\\\\\text{Divide both sides by -1, while also flipping the inequality}\\\\x\leq3\\\\\boxed{\text{Answer: C.} \,x\leq3}$

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3 years ago

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Which angle corresponds to <7? A. <1 B. <3 C. <4 D. <6

DiKsa [7]

B.

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2 years ago

Factor. 3n^4+21n^3+27n^2 Enter your answer in the box.

asambeis [7]

Factor the following:
3 n^4 + 21 n^3 + 27 n^2

Factor 3 n^2 out of 3 n^4 + 21 n^3 + 27 n^2:

Answer: 3 n^2 (n^2 + 7 n + 9)

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3 years ago

Find the distance between these points. A(5,8), B(-3,4)

konstantin123 [22]

Answer:

Distance between the points is 8.94 units

Step-by-step explanation:

General formula:

${ \boxed{ \bf{distance = \sqrt{ {(x_{1} - x _{2} )}^{2} + {(y _{1} - y _{2} ) }^{2} } }}}$

substitute:

${ \sf{ = \sqrt{ {(5 - ( - 3))}^{2} + {(8 - 4)}^{2} } }} \\ = { \sf{ \sqrt{64 + 16} }} \\ = { \sf{ \sqrt{80} }} \\ = 8.94 \: units$

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2 years ago

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Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

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3 years ago