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3 years ago

The length of a rectangular field is 4 m longer than its width.

1 answer:

7 0

We know the perimeter is the sum of all sides. So lenght+length+width+width = 2length+2width.
Let's call the width x. If the length is 4m longer, then it's x+4.
We know the perimeter, so we can make an equation:
56=2x+2(x+4)
And solve from there:
56=2x+2x+8
56=4x+8
48=4x
48/4=x
x=12

The width, which is x, is 12 m. And the length, x+4, is 16 m.
You can check this is correct by calculating the perimeter using those values: 12+12+16+16=56.

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3 0

3 years ago

Solve pls brainliest

ahrayia [7]

Answer:

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Step-by-step explanation:

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3 0

2 years ago

Read 2 more answers

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Bumek [7]

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

$(x,y)\to (x,-y)$

Now, using this rule, we get

$A(1,4)\to A'(1,-4)$

$B(3,-2)\to B'(3,2)$

$C(4,2)\to C'(4,-2)$

Therefore, the coordinates of the image A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

7 0

3 years ago

F(x)=6x-8<br> G(x)=-4x-7<br> Find 3f(x)-g(x)

miskamm [114]

3(6x-8)-(-4x-7)
18x-24+4x+7
ANSWER= 22x-17

7 0

3 years ago

How to write 1/3, 1/5 as an a common denominator as an equivalent fraction

Anni [7]

Answer:

Step-by-step explanation:

$\dfrac{1}{3}\\\\\text{List multiples of 3:}\ 0,\ 3,\ 6,\ 9,\ 12,\ \boxed{15},\ 18,\ 21,\ ...\\\\\dfrac{1}{5}\\\\\text{List multiples of 5:}\ 0,\ 5,\ 10,\ \boxed{15},\ 20,\ 25,\ ...\\\\\text{The common denominator is 15.}\\\\\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{1}{5}=\dfrac{1\cdot3}{5\cdot3}=\dfrac{3}{15}$

6 0

3 years ago