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mixas84 [53]
3 years ago
15

Write the rate in simplest form 168/8

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0
168 / 8 = 21. It is in simplest form at 21.
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What is the radius of a circle whose equation is (x + 5)2 + (y - 3)2 = 42?
finlep [7]

Answer:

the answer is 8 units so that all i have to say.

5 0
3 years ago
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Find the value of x.
Akimi4 [234]

Answer:

x = 83 degree

Step-by-step explanation:

x + 43 = 126 (sum of two interior opposite angle is equal to the exterior angle formed)

x = 126 - 43

x = 83 degree

8 0
2 years ago
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A 95% confidence interval for a population mean is computed from a sample of size 400. Another 95% confidence interval will be c
Anna [14]

Answer:

The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100

Step-by-step explanation:

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion

Generally the margin of error is mathematically represented as

      E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }    

Here assume that Z_{\frac{\alpha }{2} } \ and \  \sigma \ is constant so

     E =  \frac{k}{\sqrt{n} }

=>  E \sqrt{n} = K

=>   E_1 \sqrt{n}_1 =  E_2 \sqrt{n}_2

So  let  n_1 = 400 and n_2 =  100

=>   E_1 \sqrt{400} =  E_2 \sqrt{100}

=>  E_1 =  \frac{\sqrt{100} }{\sqrt{400} } E_2

=>  E_1 =  \frac{1}{2 } E_2

So From this we see that  the confidence interval for a sample size of 400 will be half that with a sample size of 100

   

     

   

7 0
2 years ago
PLEASE HURRY IM TIMED!!!
andriy [413]

<u>Answer-</u>

<em>A. Brandon’s sound intensity level is 1/4th as compared to Ahmad’s.</em>

<u>Solution-</u>

Given that, loudness measured in dB is

L=10\log \frac{I}{I_0}

Where,

I   = Sound intensity,

I₀ = 10⁻¹² and is the least intense sound a human ear can hear

Given in the question,

I₁ = Intensity at Brandon's = 10⁻¹⁰

I₂ = Intensity at Ahmad's  = 10⁻⁴

Then,

L_1=10\log \frac{I_1}{I_0}=10\log \frac{10^{-10}}{10^{-12}}=10\log \frac{1}{10^{-2}}=10\log 10^{2}=2\times10\log 10=20

L_2=10\log \frac{I_2}{I_0}=10\log \frac{10^{-4}}{10^{-12}}=10\log \frac{1}{10^{-8}}=10\log 10^{8}=8\times10\log 10=80

\therefore \frac{L_1}{L_2} =\frac{20}{80} =\frac{1}{4}

5 0
3 years ago
The city council wants to find out if city residents would be willing to pay higher taxes for improvements to the city's parks.
Sloan [31]
A. The council randomly surveys People from a list of city residents
6 0
3 years ago
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