The answer is B) 4 : 16
Explanation:
RATIO FOR 1 MOLECULE OF ACETIC ACID:
2 carbon atoms : 2 oxygen atoms : 4 hydrogen atoms
Since its asking how many for 2 MOLECULES, we double the ATOMS (we multiply all by 2)
RATIO FOR 2 MOLECULES OF ACETIC ACID:
4 carbon atoms : 4 oxygen atoms : 8 hydrogen atoms
The question only asks for the ratio of carbon atoms to ALL atoms. To calculate all atoms, we add 4 + 4 + 8 = 16
So if there are 4 carbon atoms and the sum of all atoms is 16, out final ratio answer is:
B.) 4 : 16
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Answer:
Where 
represent the total pressure and 
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:
And replacing we got:
Step-by-step explanation:
For this case the partial presure of carbon dioxide is given by:
Where represent the total pressure and 
the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:
And replacing we got:
The y-value of the vertex is positive 3, as shown by the +3 on the right hand side of the equation, and the x-value is -1, from the (x+1)^2 (remember, when the number is inside the brackets, flip the sign) The vertex would be (-1, 3)
If you are looking for a rigorous answer (calculus), we must find the mininum point of the equation: f(x) = (x+1)^2 + 3 f
f'(x) = 2(x+1) = 2x + 2
2x + 2 = 0
x = -1
f(1) = (-1 + 1)^2 + 3
f(1) = 0 + 3 = 3
(-1, 3)
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
