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egoroff_w [7]
3 years ago
8

You are going to join a gym and there are two options close to your workplace. gym a charges you a flat rate of $39.95 per month

. gym b charges you $14.95 per month plus $2.95 per visit.
Mathematics
2 answers:
mars1129 [50]3 years ago
5 0
We make sample calculations per month, assuming that you visit the gym x times per month. 

(1) $39.95 per month 
(2) total = $14.95 + $2.95x

If we have the value of x, it is much easier for us to determine the answer by just substituting the value of x and solve. Whichever gives the lower cost will be our answer. 
fredd [130]3 years ago
5 0

Answer: Gym A is preferred to Gym B.

Step-by-step explanation:

Since we have given that

Gym A charges as follows:

Cost of gym per month = $39.95

Fees for gym A would be

A=39.95x

Here, x denotes the number of months.

Gym B charges as follows:

Cost of gym per month = $14.95

Cost of per visit = $2.95

Fees for gym B would be

14.95x+2.95y

Here, y denotes the number of visits.

Let us assume that x = 1 month

y = 30 visits as each month has atleast 30 days.

So, Amount to be paid for gym A would be $39.95

Amount to be paid for gym B would be

14.95+2.95\times 30\\\\=14.95+88.5\\\\=\$103.45

So, we get that gym A is cheaper than gym B.

Hence, Gym A is preferred to Gym B.

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2(a³+b²+11)+1(3+a³+b+11)
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Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

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