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s2008m [1.1K]
3 years ago
15

If A = (0, 0) and B = (8, 2), what is the length of ? A. 9.41 units B. 8.25 units C. 3.16 units D. 7.75 units

Mathematics
1 answer:
Solnce55 [7]3 years ago
8 0
The correct answer that you are looking for is B.
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Find the sum. Express your answer in simplest<br> form.
Paraphin [41]

Answer:

( 3u +12) / (v^2+4)

Step-by-step explanation:

(-u+3) / (v^2+4) + ( 4u+9)/( v^2+4)

Since the denominators are the same, we can add the numerators

((-u+3) + ( 4u+9)) /( v^2+4)

Combine like terms

( 3u +12) / (v^2+4)

7 0
3 years ago
The map shows the beach area on a coordinate plane.
Vedmedyk [2.9K]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
the figure below is a square . Find the length of side x in simplest radical form with a rational denominator.
wel

Answer:

\sqrt{14}

Step-by-step explanation:

In any square with side length s, the diagonal of the square is equal to s\sqrt{2}. Since the side length of this square is \sqrt{7}, the diagonal is equal to \sqrt{7}\cdot \sqrt{2}=\boxed{\sqrt{14}}.

Alternatively, you can form two 45-45-90 triangles with the diagonal of the square. The diagonal acts as the hypotenuse for the both these triangles, and the legs of both triangles are equal to the side length of the square. To find the length of the diagonal, use the Pythagorean Theorem, which states a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

In this question, both legs are equal to \sqrt{7}, and we're solving for the diagonal, which is the hypotenuse in this case:

\sqrt{7}^2+\sqrt{7}^2=c^2,\\c^2=14,\\c=\boxed{\sqrt{14}}

4 0
3 years ago
Help bro<br><br> Identify the Terms:<br> 3x + 5x + 12 – 3 + 2x
svp [43]

Answer:

dfadfadsadas

Step-by-step explanation:

5 0
3 years ago
What is the surface area of the rectangular prism?
algol [13]

let me lie down this prism.

Check the picture below.

so the prism is really 6 rectangles stacked up to each other at the edges, so we can simply get the area of each rectangle and sum them up.

\bf \stackrel{rectangles}{\stackrel{\textit{top and bottom}}{2(3.5\cdot 9)}~~~~+~~~~\stackrel{\textit{left and right}}{2(9\cdot 5)}~~~~+~~~~\stackrel{\textit{front and back}}{2(3.5\cdot 5)}} \\\\\\ 63+90+35\implies 188

8 0
4 years ago
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