Question

Given the system of equations, what is the solution?

Answer 1

Its B. (2,1)

Hope i helped :D

Answer 2

Answer:

Given the system of equations, what is the solution?

x + 3y = 5

x - 3y = -1

The answer is {(2, 1)}

x=2 and y=1

Step-by-step explanation:

We can find the solution in two ways,the first way is  by  term elimination the equations:

$x+3y=5 (1)\\x-3y=-1 (2)\\________$

$2x=4 (3)$

We can find x with the equation (3)

$x=\frac{4}{2}\\x=2$

Now we can replace x=2 in the equation (1) to find y

$x+3y=5 (1)\\2+3y=5\\3y=5-2\\3y=3\\y=\frac{3}{3}\\y=1$

Now, we have found x and y

x=2

y=1

The second way is  clearing x from equation 1

$x+3y=5\\x=5-3y (4)$

Now, we can replace $x=5-3y$ in the equation (2)

$x-3y=-1 (2)\\(5-3y)-3y=-1\\5-6y=-1\\-6y=-6\\y=\frac{-6}{-6} \\y=1$

Now, we can replace y=1 in the equation (1), (2) or (4) to find x

We will use the equation (1)

$x+3y=5\\x+3(1)=5\\x+3=5\\x=5-3\\x=2$

We have verified that by the two forms x = 2 and y = 1