Hmm let's say
c = commercial launches
n = non-commercial launches
we know the total of launches were 53 for that year, so
c + n = 53
we also know that, whatever "c" is, "n" is "<span>was one more than three times" that
so... three times "c", 3 * c or 3c
one more than that?
3c + 1
so.. whatever "c" is, n = 3c + 1
</span>
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solve for "c", to see how many commercial launches were there
what about "n"? well, n = 3c + 1</span>