Question

Four batsmen on a cricket team had a mean of 42.5 runs the other 7 batsmen had a mea of 18 what was the mean number of scored by the entire team rounded the nearest whole mumber

Answer 1

Answer:

The mean score of the entire team is 26.909.

Step-by-step explanation:

Given that four batsmen had a mean of 42.5.

Let $\textbf{B}_{\textbf{i}$, where $i = 1, 2, 3, \hdots, 11$ denote the batsmen.

From the first statement, we have:

$\frac{B_1 + B_2 + B_3 + B_4}{4} = 42.5$

$\implies B_1 + B_2 + B_3 + B_4 = 42.5 \times 4 = \textbf{170}$

Therefore, the sum of the scores of the first four batsmen is 170.

Now, from the second statement we have:

$\frac{B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{7} = 18$

$\implies B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11} = 18 \times 7 = \textbf{126}$

That is, the sum of the scores of the remaining 7 batsmen is 126.

Now, to calculate the average(mean) of the entire team, we add the individual scores and divide it by 11.

$\implies \frac{B_1 + B_2 + B_3 + B_4 + B_5 + B_6 + B_7 + B_8 + B_9 + B_{10} + B_{11}}{11} = \frac{170 + 126}{11}$

$= \frac{296}{11}$

$= \textbf{26.90}$ which is the required answer.