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Sladkaya [172]
3 years ago
10

Which function is graphed?

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Hey there! :)

Answer:

C. {x² + 4, x < 2

    {-x + 4   x ≥ 2

Step-by-step explanation:

This is a piecewise function, where the two equations are different. They are:

y = x²+ 4

y = -x + 4

The function x² + 4 is graphed where x < 2. (< is used because the circle is open)

The function -x + 4 is graphed where x ≥ 2. (≥ is used since the endpoint is closed)

Therefore, the correct answer is:

C. x² + 4, x < 2

   -x + 4   x ≥ 2

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−9x (5x+4 ) +10 (x+3) can someone please solve his for me thank u step by step please i really need to find out how to do it
Ivahew [28]

Answer:

-45x^{2}-26x+30

Step-by-step explanation:

So first you let's divide this equation into three parts.

Part one -9x(5x+4)

  1. Step one: you have to distribute the -9x to the numbers in the parentheses. That would leave us with a -9x*5x = -45x^{2} and -9x*4 = -36x
  2. Step two: Put the answers together. That would leave us with -45x^{2}-36x.

Part two 10(x+3)

  1. Step one: you have to distribute the 10 to the numbers in the parentheses. That would leave us with a 10*x = 10x and 10*3 = 30
  2. Step two: Put the answers together. That would leave us with 10x+30

Part three solve

  1. Step one: combine and put together what you have solved for. That would leave us with a -45x^{2}-36x+ 10x+30
  2. Step two: combine like terms. The like terms here are -36x and 10x. When you combine them you would get -26x.
  3. Step three: Write the equation in standard form. Therefore the answer is -45x^{2}-26x+30.

Let me know if anything is confusing!

5 0
3 years ago
$30 is taken off the price of a dress. If the new price is now 60% off the original price, what was the original price of the dr
Alex Ar [27]
The original price of the dress is $75
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2 years ago
The proof ABC ≅ DCB that is shown.
Schach [20]

The <em><u>correct answer</u></em> is:

AAS

Explanation:

AAS stands for "angle-angle-side."  This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.

In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with.  Throughout the proof, we find that ∠ABC ≅ ∠DCB.  We also have that CB is congruent to itself.  This is two angles and a side not included, so this is AAS.

4 0
3 years ago
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