URGENT!
1 answer:
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Answer:
D. y²/5² - x²/8² = 1
Step-by-step explanation:
A and B are both incorrectly oriented, and D is the only hyperbola that contains the points (0,5) and (0,-5).
Verification (0,5) and (0,-5) are in the hyperbola:
First replace x and y with corresponding x and y values (We will start with x=0 and y=5)
Then simplify.
If the result is an equation (where both sides are equal to each other) then the original x and y values inputted are valid. The same is true with x and y inputs x=0 and y=-5, or any other point along the hyperbola.
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Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...
Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.