As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
Answer:
yo soy inteligente
Step-by-step explanation:
pero no me se la respuesta de la perunta
7x+7b = 7(x+b)
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Answer:
437-418=19
Step-by-step explanation:
418+19=437
Answer:
6/10
Step-by-step explanation:
how to solve this equation look at 3/5 that is together the separate and do 3×2 and 5×2 then equals to 6/10 because fraction is multiply to last number after the original number
