The height (in feet) of a certain rocket t seconds after it leaves the ground is modeled by

Mathematics

1 answer:

wolverine [178]3 years ago

7 0

Answer:

The answer is 1/2 second

Step-by-step explanation:

Hope this helps

You might be interested in

How do you do this??

astra-53 [7]

welll...you have there written just one relationship...it is berween 280 and 4 hours...you have to figure out speed:

$280 \div 4 = 70$

it is speed per hour

then you just connect time and speed:

140 - 2
280 - 4
350 - 5
420 - 6
560 - 8
700 - 10

6 0

3 years ago

What is the equation of a circle with its center at (10,−4) and a radius of 2?

Dmitrij [34]

Equation of circle
(x-h)^2 + (y-k)^2 = r^2
=> (x-10)^2 + (y+4)^2 = 4 is the answer

7 0

3 years ago

Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3

Veronika [31]

Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3

5 0

3 years ago

Can someone help me ? And show me the steps

kow [346]

If the line is parallel, it has the same slope. So now just find the y intercept and put it into slope-intercept form

3 0

3 years ago

The product of (3 − 4i) and____is 25.

LiRa [457]

$(3-4i)(a+bi)=25\qquad\text{use FOIL method}\\\\(3)(a)+(3bi)+(-4i)(a)+(-4i)(bi)=25+0i\\\\3a+3bi-4ai-4bi^2=25+0i\\\\3a+3bi-4ai-4b(-1)=25+0i\\\\3a+3bi-4ai+4b=25+0i\\\\(3a+4b)+(3b-4a)i=25+0i\\.\qquad\qquad\qquad\qquad\Downarrow\\\\3a+4b=25\ and\ 3b-4a=0\\\\3b-4a=0\qquad\text{add 4a to both sides}\\\\3b=4a\qquad\text{divide both sides by 3}\\\\b=\dfrac{4}{3}a\qquad\text{substitute it to the first equation}\\\\3a+4\left(\dfrac{4}{3}a\right)=25\\\\3a+\dfrac{16}{3}a=25\qquad\text{multiply both sides by 3}$

$9a+16a=75\\\\25a=75\qquad\text{divide both sides by 25}\\\\\boxed{a=3}\qquad\text{put the value of a to}\ b=\dfrac{4}{3}a:\\\\b=\dfrac{4}{3}(3)\\\\\boxed{b=4}\\\\Answer:\ \boxed{(3-4i)\underline{(3+4i)}=25}$

6 0

3 years ago