Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Use the slope formula which is y2-y1/x2-x1. -1-4/5-(-2)= -5/7
Answer:
20%
Step-by-step explanation:
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Answer:
Slope:-63
Y-intercept: (0,825)
Step-by-step explanation:
Slope= y2-y1 ÷ x2-x1
321-699 ÷ 8-2
-378 ÷ 6 =-63
Y-intercept:
y=-63x+b
to get b (y-intercept) plug in one of the points and solve.
699=-63(2)+b
699=-126+b
699+126=-126+126+b
699+126=0+b
825=b
85 is the correct answer.
