Answer:
9. Triangle ABQ is congruent to Triangle BAP because of SAS congruency
10. x=5, y isn't shown anywhere
Step-by-step explanation:
9. The side AB is shared between the two triangles.
It is given that angle A and angle B are congruent.
It is given that AQ is congruent with BP.
Using these three, you can say that Triangle ABQ is congruent to Triangle BAP because of SAS congruency.
10. 7x-4=31 (given)
x=5
Do the same thing with y.
Answer:
x difference is 8
Step-by-step explanation:
Y values are the same so just find the difference in -4 and 4
Time wind time speed divide by 3
Hi there! :)
h(x) = 1/2x + 4
Substitute in -4 for "x" to solve for h(-4):
h(-4) = 1/2(-4) + 4
h(-4) = -2 + 4
h(-4) = 2
Since we are solving for h(-4) + 2, add:
2 + 2 = 4.
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
