The possible values of x for the following functions are values on real number except 0 and 1
<h3>Domain of a function</h3>
The domain of a function are the values of the independent variable for which it exists.
Given the function below
f(x)=2-x/x(x-1)
The function does not exist at the. point where the denominator is zero. From the function given, the function does not exist when;
x(x -1) = 0
x = 0 and x = 1
Hence the possible values of x for the following functions are values on real number except 0 and 1
Learn more on domain of a function here; brainly.com/question/1770447
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<span>f(x) = x</span>² <span>+ 12x + 6 </span>→ y = x² + 12x + 6<span>
Let us convert the standard form into vertex form.
1) Complete the squares. Isolate x</span>² and x terms.
<span>y - 6 = x</span>² + 12x
<span>
2) Create the perfect square trinomial. Whatever number is added on one side must also be added on the other side.
y - 6 + 36 = x</span>² + 12x + 36<span>
y + 30 = (x + 6)</span>²
<span>y = (x + 6)</span>² - 30 ← Vertex form
<span>
To check:
y = (x + 6) (x + 6) - 30
y = x</span>² + 6x + 6x + 36 - 30
<span>y = x</span>² + 12x + 6<span>
The zero that could be added to the given function is 36, -36</span>
I'd say it's x + 1 < 17.
Because the operator should be included as a person as well.
The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.
Answer:
A
Step-by-step explanation:
