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3 years ago

PLEASE HELP I forgot how to do this and it’s for a final :((

Mathematics

1 answer:

natima [27]3 years ago

8 0

F(x)= 2/(x+1) and g(x)= -x2-12 => f(-7)= ? , g(2.5)= ?, g(f(- 0.5))= ?
In the expression of the function f(x) we will replace instead of x the number in bracket (-7) => f(-7) = 2/(-7+1)= 2/-6 = - 1/3
In the expression of the function g(x) we will replace instead of x number in bracket (2.5) => g(2.5) = - (2.5)squared -12= - 6.25 -12= - 18.25
Expression f(g(x)) or g(f(x)) is multiplication (composition) of the reflecting of functions f and g. We will do this in the following way => g(f(x))= g(2/(x+1))= -(2/(x+1))2 - 12= -(4/(x+1)2) -12= -4-12(x+1)2/(x+1)2=> we will replace instead of x the number in bracket (-0.5) or (-1/2) => g(f(-1/2) = -4-12((-1/2)+1)2/ ((-1/2+ 1)2= -4-12(1/2)2/(1/2)2=-4-12*(1/4)/(1/4)= (-4-3)/(1/4)=-28
Eaisier way => f(-1/2)=2/((-1/2)+1)=2/(1/2)= 4 g(4) -(4)2-12 = -16-12= -28

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Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12

Afina-wow [57]

Hey there, hope I can help!

$\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}$

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$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \ \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}$

Hope this helps!

5 0

3 years ago

Please help me with Part C of this question!!!

anzhelika [568]

Answer:

a. 3/4 inches per minute

b. -1 1/8 inches per minute

c. B is fastest; 1 1/8 is more than 3/4

Step-by-step explanation:

A <em>change</em> is a <em>difference</em>. A <em>rate of change</em> is <em>one difference divided by another</em>, usually the change in y-value divided by the change in x-value.

The change in elevation is the difference between the elevation at the end of the period (6 inches) and the elevation at the beginning of the period (3 inches). The change in time period is the difference between the end time (8 min) and the beginning time (4 min).

change in elevation per minute = (6 -3 inches)/(8 -4 min)

= (3 inches)/(4 min) = 3/4 inches/minute

Similarly, ...

change in elevation per minute = (3 -7 1/2 inches)/(18 -14 min)

= (-4 1/2 inches)/(4 min) = -1 1/8 inches/minute

We know that 3/4 is more than -1 1/8, but when we talk about the "fastest rate of change", we're generally interested in the magnitude--the value without the sign. That means we understand a rate of change of -1 1/8 inches per minute to be "faster" than a rate of change of 3/4 inches per minute.

The rate of change from Part B is fastest. 1 1/8 inches per minute is more than 3/4 inches per minute.

6 0

2 years ago

What is the length of the hypotenuse of the triangle when x=7?

Anika [276]

Answer:

c=57.8

Step-by-step explanation:

6*7+4=46

5*7=35

c= 46^2+35^2=57.80138

7 0

3 years ago

Which equation can be solved by using this system of equations?

andrew11 [14]

the equation that we can solve using the given system of equations is:

3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0

<h3>Which equation can be solved using the given system of equations?</h3>

Here we have the system of equations:

y = 3x^5 - 5x^3 + 2x^2 - 10x + 4

y = 4x^4 + 6x^3 - 11

Notice that both x and y should represent the same thing in both equations, then we could write:

3x^5 - 5x^3 + 2x^2 - 10x + 4 = y = 4x^4 + 6x^3 - 11

If we remove the middle part, we get:

3x^5 - 5x^3 + 2x^2 - 10x + 4 = 4x^4 + 6x^3 - 11

Now, this is an equation that only depends on x.

We can simplify it to get:

3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0

That is the equation that we can solve using the given system of equations.

If you want to learn more about systems of equations:

brainly.com/question/13729904

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1 year ago

Look at this graph:

Sergio [31]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

7 0

3 years ago