Remember you can add like terms exg, 3y+4y=7y 3y^2+4y^2=7y^2, but cannot add 3y^2 and 4y, or 3 and 4y so
3a+2w-5a-9w
group like trems
3a-5a+2w-9w
subtract
-2a-7w
3y^2+2w^2-y^2-w^2
group like terms (think of w^2 and y^2 as 1w^2 and 1y^2)
3y^2-y^2+2w^2-w^2
subtract
2y^2+w^2
2x+2x=4x
14=6+2x
subtract 6 from both sides
8=2x
divide both sides by 2
x=4 candy bars
So if we want to know the common solution(s) to a system of 2 equations, So we can just set both equations equal to each other and solve for the x value(s). That’s where I start below;
2x^2-13x+21 = 2x^2+9x-56
2x^2 cancels out and moving everything to one side and anything with an x variable to the other side we have then;
-22x=-77
22x=77 by cancelling the negative signs
x=77/22 therefore x=7/2 or 3.5
Hope this helps you. Any questions please ask.
Answer:
7x⁴ + 5x³ + 7x² + 6x + 5
Step-by-step explanation:
The given expression is
(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)
The first step is to open the brackets by multiplying each term inside each bracket by the term outside each bracket. Since the term outside each bracket is 1, the expression becomes
5x⁴ + 5x³ + 4x - 9 + 2x⁴ + 7x² + 2x + 14
We would collect like terms by combining each term with the same exponent or raised to the same power. The term would be arranged in decreasing order of the exponents. It becomes
5x⁴ + 2x⁴ + 5x³ + 7x² + 4x + 2x - 9 + 14
7x⁴ + 5x³ + 7x² + 6x + 5
