<span>GCF (12,32) = 4
4 is your answer</span>
Answer:
155
Step-by-step explanation:
Using the recursive formula and a₁ = 1, then
a₂ = 3a₁ + 2 = 3(1) + 2 = 3 + 2 = 5
a₃ = 3a₂ + 2 = 3(5) + 2 = 15 + 2 = 17
a₄ = 3a₃ + 2 = 3(17) + 2 = 51 + 2 = 53
a₅ = 3a₄ + 2 = 3(51) + 2 = 153 + 2 = 155
Thus the 5 th term is 155
4x + 6 < -6
subtract 6 from both sides
4x < -12
divide 4 on both sides
x < -3
Answer: the incubation time that separates the bottom 2.5% from the rest of the incubation times is 24.96 days.
Step-by-step explanation:
Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times.
µ = mean time
σ = standard deviation
From the information given,
µ = 23 days
σ = 1 day
The probability value for the incubation time that separates the bottom 2.5% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975
Looking at the normal distribution table, the z score corresponding to the probability value is 1.96
Therefore,
1.96 = (x - 23)/1
x = 1.96 + 23
x = 24.96
Answer:
3 games and 6 rides
Step-by-step explanation:
