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never [62]
3 years ago
15

HELP MATH PLEASE ASAP!!!

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0
1.)2nd choice
2.)no solution
3.)-6
4.)one solution
lakkis [162]3 years ago
4 0
3. 2z + 7 = -5
    2z = -12
    z = -6

4. B

5. infinitely many solutions

6. one solution
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Prove that the diagonals of a rectangle bisect each other.
Umnica [9.8K]

Answer:

2

Step-by-step explanation:

example A(2a,0),B(2b,0)

C(2b,2c),D(2a,2c)

mid point of AC=((2a+2b)/2,(0+2c)/2)=(a+b,c)

mid point of BD=((2b+2a)/2,(0+2c)/2)=(a+b,c)

∴midpoint of diagonals same or diagonals bisect each other.

7 0
3 years ago
Add polynomials<br> Simplify:<br> (-5a^3 - 2a^2) + (6a^3+9a^2+8a)
Pie
Combine like terms: Then solve

(-5a3 + 6a3) + (-2a2 +9a2) + 8a =


8 0
3 years ago
Read 2 more answers
which functions have a range of all real numbers ? check all that apply. A. y=csc x B. y=sec x C. y=tan x D. y= cot x
Natalka [10]

None of these. All of these functions are defined as ratio of trigonometric functions.

Trigonometric functions have infinite zeroes, so when you put them in the denominator, they lead to infinitely many points of ill-definition.

Specifically, we have:

\csc(x) = \dfrac{1}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

\sec(x) = \dfrac{1}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\tan(x) = \dfrac{\sin(x)}{\cos(x)}

which is undefined at

\cos(x)=0\iff x=\dfrac{\pi}{2}+k\pi, k\in\mathbb{Z}

\cot(x) = \dfrac{\cos(x)}{\sin(x)}

which is undefined at

\sin(x)=0\iff x=k\pi, k\in\mathbb{Z}

4 0
3 years ago
18. The sum of 'l6, /3, and 'Is is
lys-0071 [83]

Answer:

wn work

Step-by-step explanation:

3 0
3 years ago
Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person,
crimeas [40]

Answer:

No it cannot be concluded.

Step-by-step explanation:

The probability of getting the disease in the first attempt is 50%

The probability of getting the disease in the second attempt is 50%

Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)

BUT

The probability of not  getting the disease in the first attempt is 50%

The probability of not getting the disease in the second attempt is 50%

Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)

Thus the probability of getting the disease in either of the 2 contacts is still 50%

4 0
3 years ago
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