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2 years ago

HELP MATH PLEASE ASAP!!!

Mathematics

2 answers:

Delicious77 [7]2 years ago

8 0

1.)2nd choice
2.)no solution
3.)-6
4.)one solution

lakkis [162]2 years ago

4 0

3. 2z + 7 = -5
2z = -12
z = -6

4. B

5. infinitely many solutions

6. one solution

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Rudiy27

Answer:

$x1=\frac{5+\sqrt{37}} {6}$

$x2=\frac{5-\sqrt{37}} {6}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

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in this problem we have

$3x^{2} -5x-1=0$

$a=3\\b=-5\\c=-1$

substitute in the formula

$x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}$

$x=\frac{5(+/-)\sqrt{37}} {6}$

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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