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never [62]
3 years ago
15

HELP MATH PLEASE ASAP!!!

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0
1.)2nd choice
2.)no solution
3.)-6
4.)one solution
lakkis [162]3 years ago
4 0
3. 2z + 7 = -5
    2z = -12
    z = -6

4. B

5. infinitely many solutions

6. one solution
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Which circle corresponds to the equation<br> (x – 4)2 + (y + 4)2 = 25
Verdich [7]

Answer:

The red one corresponds to that equation

Step-by-step explanation:

Believe me

5 0
3 years ago
Help ! With step by step solution
nirvana33 [79]

Answer:

the correct answer is C

Step-by-step explanation:

first step you change the x and y powers to the square root(showing in the pic).

second the number outside of the parenthesis times the numbers inside the parenthesis and then you just figure it out how it works...

7 0
3 years ago
What is the GCF of 20 and 36
ASHA 777 [7]

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

GCF(20, 36) = 4

Answer: b). 4

6 0
3 years ago
Read 2 more answers
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
What is the smallest solution to the equation 2x^2+17=179
Jobisdone [24]
The goal is to put the equation in the simplest form to solve:
2x²+17=179

Subtract both sides by 17.
179-17= 162
2x²=162

Square root 162.
√162 = 12.7 (rounded)
2x=12.7

Divide both sides by 2.
12.7/2= 6.4 (rounded)
x=6.4

The variable x is 6.4, rounded to the nearest tenth for simple purposes.

Hope this was helpful.
3 0
4 years ago
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