Answer:
1.08
Step-by-step explanation:Simplify the radical by breaking the radicand up into a product of known factors.
9514 1404 393
Answer:
3
Step-by-step explanation:
For f(x) = x^3 -2x^2 -7x +5 and x=1/(2-√3), we have ...
f(x) = ((x -2)x -7)x +5
and ...
x = 1/(2-√3) = (2+√3)/(2^2 -3) = 2+√3
Then ...
f(2+√3) = ((2 +√3 -2)(2 +√3) -7)(2 +√3) +5
= (3+2√3 -7)(2+√3) +5
= 2(√3 -2)(√3 +2) +5 = 2(3 -4) +5 = -2 +5
f(1/(2 -√3)) = 3
_____
If you really mean x = (1/2) -√3, then f(x) = (42√3 -3)/8.
Answer:
Twelve tickets cost $30 --> True
Thirty tickets cost $12 --> False
Each additional costs $2.50 --> True
The table is a partial rep --> True
ordered pairs --> False
Step-by-step explanation:
Twelve tickets cost $30 --> True, you can literally see that in the table
Thirty tickets cost $12 --> False, 30 is not in the table so you don't have that information. Besides, $12 is an unlikely low value for so many tickets.
Each additional costs $2.50 --> True, you can see the difference in the TotalCost column to be consistently 2.50.
The table is a partial rep --> True, values below 11 are not shown for example.
ordered pairs --> False --> Then the x value should be first, e.g., (11, 27.50), since the cost y is a function of the number x.
Answer:
24.24%
Step-by-step explanation:
In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12
Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.
or 0.2424 or 24.24%
Answer:
y = 6x - 47
or
6x - y - 47 = 0
Step-by-step explanation:
