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Margarita [4]
3 years ago
12

14. Solve: 3x² + 5x – 12 = 0B. 4-3C. 8, - 18​

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
7 0

Answer:

b

Step-by-step explanation:

The equation:

3

x

2

−

5

x

−

12

=

0

is in the form:

a

x

2

+

b

x

+

c

=

0

with  

a

=

3

,  

b

=

−

5

,  

c

=

−

12

The roots are given by the quadratic formula:

x

=

−

b

±

√

b

2

−

4

a

c

2

a

x

=

5

±

√

(

−

5

)

2

−

4

(

3

)

(

−

12

)

2

(

3

)

x

=

5

±

√

25

+

144

6

x

=

5

±

√

169

6

x

=

5

±

13

6

That is:

x

=

5

+

13

6

=

18

6

=

3

 

or  

 

x

=

5

−

13

6

=

−

8

6

=

−

4

3

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Step-by-step explanation:

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an office supply company sells two types of printers. they charge $95 for one of the printers and $125 for the other. if the com
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Answer:

22 of the 95$ ones and 10 of the 125

Step-by-step explanation:

22 times 95 = 2090

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4 0
2 years ago
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0
3 years ago
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olga55 [171]

Answer:

3, 12, 27 and 300

Step-by-step explanation:

Plug n as 1, 2, 3 and 10.

3(1)² = 3

3(2)² = 12

3(3)² = 27

3(10)² = 300

8 0
3 years ago
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vaieri [72.5K]

Answer:

4.45

Step-by-step explanation:

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4 0
2 years ago
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