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Serga [27]
3 years ago
14

On a street, each house has an address between 1000 and 1099, inclusive. at least how many houses are there if at least two of t

hem have addresses that are consecutive integers
Mathematics
1 answer:
notsponge [240]3 years ago
8 0
There are at least 3 houses on a street if at least two of them have addresses that are consecutive integers.
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I don’t remember how I get the answer to this. I have the answer key though. Please help, I have a test in an hour
mrs_skeptik [129]

Answer:

  f(x) = (x -2)(x -1+3i)(x -1-3i)

Step-by-step explanation:

You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.

In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.

Of course, you know that for zeros a, b, and c, the linear factors are ...

  f(x) = (x -a)(x -b)(x -c)

Here, we have a=2, b=1-3i, c=1+3i.

  f(x) = (x -2)(x -1+3i)(x -1-3i)

5 0
3 years ago
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:) Simplify 2^4 x 2^6 / 2^5
Sladkaya [172]

Answer:

2^5

Step-by-step explanation:

2^4 × 2^6 ÷ 2^5

= 2^10 ÷ 2^5

=2^5

8 0
3 years ago
∠1 and​ ​ ∠2 ​ ​are complementary angles.
Gwar [14]
Angle two would be 180-m<1

180-52= 128

Measurement of angle two is 128 degrees
5 0
3 years ago
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If I had seven stones and I threw 8 how many stones do I have left??
igomit [66]
It is impossible as 8 is bigger than 7 and you can’t take it away ur welcome
7 0
3 years ago
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Write an inequality for the graph.
ivann1987 [24]

Use y = mx + b to determine the equation of the graph, then decided the inequality symbol.

m = +5/+6 = \frac{5}{6}    b = 5

y =  \frac{5}{6}x + 5

6y = 5x + 30

-30 = 5x - 6y   ⇒   5x - 6y = -30

Now let's look at the inequality symbol:  The shaded area is below so it will be a less than symbol and it is a solid line so the equal sign is included.

Answer: 5x - 6y ≤ -30



7 0
3 years ago
Read 2 more answers
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