Adam's average speed = 40 miles per hr
time for the trip = 30 minutes = 0.5 hrs
Distance travelled by adam = speed * time = 40 * 0.5 = 20 miles
Distance travelled by Beth is 5 miles longer means 20 + 5 = 25 miles
Time took by Beth is 20 minutes more means = 30 + 20 = 50 minutes = 0.83 hrs
Average speed of Beth = distance / time = 25 / 0.8333
Average speed of Beth = 30 miles : Answer
Hope it will help :)
Answer:
like terms
Step-by-step explanation:
they all are terms that include the letter x
Answer:
4+y < 15
the best i can do
Step-by-step explanation:
Answer:
Incomplete question
Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.
a. Determine the pre-collision momentum of the ball.
b. Determine the post-collision momentum of the ball.
c. Determine the momentum change of the ball.
Answer:
A. 1.5353kgm/s
B. 1.6963kgm/s
C. 0.161kgm/s
Step-by-step explanation:
A. The pre-collision momentum of the ball = mass of ball × velocity of ball
Mass of ball = 57.5g = 0.0575kg
Velocity of ball = 26.7m/s
Pre-collision momentum of ball = 0.0575×26.7
= 1.5353kgm/s
B. Post collision momentum of the ball = mass of ball × velocity of ball after impact
Velocity of ball after impact = 29.5m/s
Post collision momentum of ball after impact = 0.0575×29.5
= 1.6963kgm/s
C. Momentum change of ball = momentum after impact - momentum before imlact
= 1.6963kgm/s - 1.5353kgm/s
= 0.161kgm/s
Step-by-step explanation:
the distance is sqrt ( (-6)^2 + (-12)^2) = sqrt( 36 + 144) = sqrt( 180) = sqrt(36*5) = 6 * sqrt(5)
2/(2+4) = 2/6 = 1/3
-2 + (1/3)*6*sqrt(5) = -2 + 2* sqrt(5)
6 + (1/3)*6*sqrt(5) = 6 + 2* sqrt(5)
