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Monica [59]
3 years ago
15

Simplify the expression (-4)(9)/(-6)6–3636–6

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0

(-4)(9)/(-6)

= -36/(-6)

= 6 answer

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Nigel and Mia are searching for a treasure chest under water. The straight line distance between them is 100 meters.
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I'm pretty sure its B.

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What is the missing numerator of 4/9= ?/81
yKpoI14uk [10]
To solve this question, first cross multiply
Let ? = x

4/9 = x/81

4(81) = 9(x)

Simplify.

81 x 4 = 324

324 = 9x

Isolate the x, divide 9 from both sides

324/9 = 9x/9

x = 324/9

x = 36


4/9 = 36/81

36 is your answer

hope this helps!
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Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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