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AnnyKZ [126]
3 years ago
14

Drag expressions into order to show a way to find 3 × 56.

Mathematics
2 answers:
ikadub [295]3 years ago
8 0
Where is the picture :) ?
lina2011 [118]3 years ago
7 0
As we could "drag" these together, we could then do it the easy way.

  56
+56
+56
-------
168
------------------------

Or we could also do the following:

56*3:

6*3= 18.

Carry the one. 

5*3 = 15+1 (which was carried). = 16

(16+8) = 168





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Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
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Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

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