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AnnyKZ [126]
3 years ago
14

Drag expressions into order to show a way to find 3 × 56.

Mathematics
2 answers:
ikadub [295]3 years ago
8 0
Where is the picture :) ?
lina2011 [118]3 years ago
7 0
As we could "drag" these together, we could then do it the easy way.

  56
+56
+56
-------
168
------------------------

Or we could also do the following:

56*3:

6*3= 18.

Carry the one. 

5*3 = 15+1 (which was carried). = 16

(16+8) = 168





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I will mark brainliest IF CORRECT
umka2103 [35]

Answer:

1 - (π/6) - (√3/4)

Step-by-step explanation:

First, calculate the area of ABCD. That's just 1*1 = 1 un^{2}

Then, we are told that arcs BD and AC are circular, meaning they are portions of a circle. Therefore, let's redraw this image a little. Look below for the image.

Essentially, what I've done is created an equilateral triangle and two sectors. You may be wondering why the triangle is equilateral. Well, we firstly know it's isosceles because the two original arcs are circular and congruent. Their overlap creates two congruent lines that can be extend from point M to the vertices A and D. These two lines also happen to be radii of the quarter circles because the two sectors have AM AND AD as radii. AM and AD = 1, so AMD is an equilateral triangle.

Draw altitude OD. This is a right angle. Since equilateral triangles are also isosceles triangles, and isosceles triangles have the property of sharing the median to base and altitude to base, we can say that OD = \frac{1}{2} AD = \frac{1}{2}. MD = 1, so this triangle is a 30-60-90 triangle. Why? This is because of the 30º angle converse theorem. The shorter leg is half of the hypotenuse MD, so <OMD is a 30º angle, making <ODM a 60º angle and inevitably <MDC a 30º angle (because <D is a right angle) and <ABM as well because the two sectors are congruent.

Because m<ABM = m<MDC = 30º, these two sectors are 30/360 of the individual circles or 1/12 of the original circles, which have areas of π (because 1^2*π = π). Each is 1/12π, combined they are 1/6π.

The area of the equilateral triangle is √3/8. This is because MO can be calculated, using the 30-60-90 ratios, to be √3/2. (1 * √3/2)/2 = (√3/2)/2 = √3/4; this uses the area of a triangle. Now, time to calculate the shaded area.

The area of the square is 1, the area of the sectors π/6, and the equilateral triangle √3/4. Subtract the equilateral triangle and sectors' areas from the area of the square to be left with the remaining shaded part. 1-(π/6)-(√3/4) is your final answer. To put that a little more cleanly below in the image.

Hope this helps, have a great day.

3 0
2 years ago
Name the types of angles shown
Karo-lina-s [1.5K]

Answer:

B) supplementary angles

C) straight angle

Step-by-step explanation:

There is a straight line, and when an angle is a straight it means its 180 degrees which makes it a supplementary angle and a straight angle.

There are no angles that are 90 degrees so its not complementary or a right angle.

8 0
3 years ago
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Klio2033 [76]
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3 years ago
In a transformation, the final figure is called.
Viktor [21]

Answer:

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation.

6 0
3 years ago
The circumference of a circular pond in the park is 120 meters. Find the area.
Tpy6a [65]

Answer:

1) 38

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Step-by-step explanation:

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