Question

A rectangle has a width of 9 inches and a length of 15 inches. If the rectangle is enlarged by a scale factor of 3/2, what is the perimeter of the dilated rectangle

Answer 1

Answer:

P = 48 in²

Step-by-step explanation:

Given: A rectangle; Width = 9 inches, length = 15 inches, enlarged by a scale factor of $\frac{3}{2}$

To find: Perimeter of the dilated rectangle

Formula: $P=2(l+w)$

Solution: After a dilation with a scale factor of one-half, then the lengths on the image would be one-half , one-half , and one-half . To find the perimeter of an enlarged figure, you can multiply the original figure's perimeter by the scale factor.

$P=2(l+w)=2$ × $(15+9)=48in$

Therefore, the perimeter of the detailed rectangle that was enlarged is 48 in²