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4 years ago

Find the absolute maximum value for the function f(x) = x2 – 3, on the interval [–4, 0) U (0, 3].

Mathematics

1 answer:

BigorU [14]4 years ago

7 0

13 will be the answer. Plug in -4 into the equation

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What is the measure of the angle x?

navik [9.2K]

AOB = 2 . x
2x = 60°
x = 30°

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3 years ago

Can anyone help me with this one please

bulgar [2K]

A. 314 sq cm

Explanation: pi•r^2
3.14 x 10^2
3.14 x 100 =314

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3 years ago

Please help please these are short answers

atroni [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows:

(19) Weight of the puppy last week is

$W_\ell=2\dfrac{1}{2}~\textup{lb},$

and weight of the puppy this week is

$W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.$

Therefore, the weight gained by the puppy is given by

$W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.$

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

$H_\ell=\dfrac{4}{9}~\textup{hr},$

and the time taken by Nazia to complete her Mathematics homework is

$H_m=\dfrac{2}{9}~\textup{hr}.$

Therefore, Nazia takes more time to complete Language Arts homework, by

$H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.$

(22) Quantity of Aluminium collected by Maya is

$A_m=\dfrac{4}{20}=0.2~\textup{lb},$

and the quantity of Aluminium collected by her friend Abigail is

$A_a=\dfrac{7}{8}=0.87~\textup{lb}.$

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

$T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.$

(23) Quantity of snow fall last Wednesday is

$S_w=3\dfrac{1}{4}=3.25~\textup{in.},$

and quantity of snowfall on sunday is

$S_s=3\dfrac{4}{5}=3.8~\textup{in.}.$

Therefore, quantity of snowfall was more on Sunday by

$S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.$

Thus, all the questions are answered.

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3 years ago

35 POINTS, Please help me with this high school geometry question.

Pani-rosa [81]

Answer:

A: part 1:

A. (-5,6)

B. (2,5)

C. (-2,-4)

Step-by-step explanation:

B: Part 2:

A. (-2,4) ---> (-5,6): moved left 3 times, moved up 2 times.

B. (5,3) ----> (2,5): moved left 3 times, moved right 2 times.

C. (1,-6) ----> (-2,-4): moved left 3 times, moved right 2 times.

Hope this helps you!! (:

5 0

4 years ago

How to calculate roots when the equation is non quadratic?

likoan [24]

Solve like a linear algebra equation
$y = mx + b$
use for slope
$m = y1 - y2 \div x1 - x2$
the b is intersept

5 0

3 years ago