2 years ago

How do you find the distance around a triangle that had sides measuring 2-1/8 feet, 3-1/2 feet, and 2-1/2 feet?

Mathematics

1 answer:

tatuchka [14]2 years ago

6 0

1. Turn the fractions in to decimals
2.Add them up

2.13 + 3.5 + 2.5 = 8.13ft

You might be interested in

A kite flying in the air has a 78-string attached to it, and the string is pulled taut. The angle of elevation of the kite is 52

Basile [38]

Answer:

sine 52 degrees = height / 78

height = 78 * sine 52

height = 78 * 0.78801

height = 61.46478 feet

rounded to nearest tenth 61.5 feet

Step-by-step explanation:

5 0

2 years ago

What is the value of k in the equation k\3 -5=34

Alex

If wrong i apologize but for that equation i got the answer K=117

4 0

3 years ago

Read 2 more answers

What is the equation of a line that is perpendicular to the y-axis and goes through point (-1,-8).

Wittaler [7]

Y= -1

it’s a horizontal line that is perpendicular to the y-axis

4 0

2 years ago

What is the equation of the line that passes through the point <br> (1,0) and has a slope of 1?

soldier1979 [14.2K]

Answer:

y=x+1

Step-by-step explanation:

$1 = 1 \times 0 + b \\ 1 = 0 + b \\ 1 = b \\ y = x + 1$

7 0

3 years ago

Consider a cylinder with radius 4 cm and a height of 12 cm. Describe how to calculate the volume of the given cylinder and what

Talja [164]

$\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\ -----\\ r=\stackrel{cm}{4}\\ h=\stackrel{cm}{12} \end{cases}\implies V=\pi (4)^2(12)\implies V=192\pi~cm^3$

192π is about 603.19 cm³.

well, it means if you grab a hmmmm cube, say that is 1cm x 1cm x 1cm, namely a 1cm tall, 1cm wide and 1cm long, whose value is 1cm³, you can fit 603.19 of those in that cylinder.

5 0

3 years ago